ch3conh2 lialh4



ch3conh2 lialh4

Reduction of amide The Student Room

Question : Treat CH3CONH2 with LiAlH4 in dry ether followed by the treatment of water produces . A) CH3CH(OH)NH2. B) CH3CH2NH2 The answer is A or B Appreciate your reply ^ ^ This was posted from The Student Room''s iPhone/iPad App

Complete the following: CH3CH2CN + LiAlH4 → A +

Complete the following: CH3CH2CN + LiAlH4 → A + 0°C/HNO2 → B CH3CONH2 + HNO2 > asked Dec 29, 2017 in Chemistry by sforrest072 (128k points) aldehydes ketones and carboxylic acids; 0 votes. 1 answer. In the following sequence of reactions CH3 Br + KCN → A + H3O^+ → B + LiAlH4/ether → C,

[Solved] Which of the following reactions will not give

Which of the following reactions will not give primary aminea) CH3CONH2 + KOH.Br2b) CH3CN + LiAlH4. Which of the following reactions will not give primary amine a) CH3CONH2 + KOH.Br2. b) CH3CN + LiAlH4. c) CH3NC + LiAlH4. d) CH3CONH2 + LiAlH4

中南大学有机化学—第九章羧酸及其衍生物 百度文库

RCOOH LiAlH4 or B2H6 乙醚 H2O RCH2OH 实例 CH3CH3CH2COOH LiAlH4 CH3CH2CH2CH2OH CH2=CHCH2COOH LiAlH4 CH2 3 + H 2O 2 CH3COOH CH3COOC2H5 + H2O H 或OH CH3COOH + C2H5OH 酯需要在催化剂存在下水解 CH3CONH2 + H2O

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