# a centrifuge rotor rotating at 10300 rpm

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## A centrifuge rotor rotating at rpm is shut off

A centrifuge rotor rotating at rpm is shut off and is eventually brought uniformly to rest by frictional torque of 1.20 Nm. If the mass of the rotor is 4.80 kg and it can be approximated as a solid cylinder of radius 0.0710 m, through (i) how many revolutions will the rotor turn before coming to rest, (ii) how long will it take, and (iii) what is it''s angular momentum

## Solved > Question A centrifuge rotor rotating at 10,300

A centrifuge rotor rotating at 10,300 rpm is shut off and is eventually brought uniformly to rest by a frictional torque of 1.2 m*N. If the mass of the rotor is 4.8 kg and it can be approximated as a solid cylinder of radius.0710 m, through how many revolutions

## Chapter 10 Problem 48 105/106 Lecture Notes by OBM

A centrifuge rotor rotating at rpm is shut off and is eventually brought uniformly to rest by a frictional torque of 1.20 m.N. If the mass of the rotor is 3.80 kg and it can be approximated as a solid cylinder of radius 0.0710 m, through how many revolutions will the rotor turn before coming to rest, and how long will it take Solution

## SOLVED:(II) A centrifuge rotor rotating at 10,300 \mathrm

question Number 37. That park is equal to the movement off inertia into angular acceleration. Park is given as 1.2 Newton meters and more in both. Financial is

## Problems w/ rotational dynamics and angular momentum

) A centrifuge rotor rotating at 10,300 rpm is shut off and is eventually brought uniformly to rest by a frictional torque of 1.20 mN.

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